SA=418*10^23/A*TBq/a eching

$$S A = \frac { 418 \times 10 ^ { 23 } } { A \times T } \frac { B q } { a }$$

B uchun yechish (complex solution)

$$\left\{\begin{matrix}B=\frac{STaA^{2}}{41800000000000000000000000q}\text{, }&q\neq 0\text{ and }A\neq 0\text{ and }T\neq 0\text{ and }a\neq 0\\B\in \mathrm{C}\text{, }&S=0\text{ and }q=0\text{ and }A\neq 0\text{ and }T\neq 0\text{ and }a\neq 0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tenglamaning ikkala tarafini ATa ga, AT,a ning eng kichik karralisiga ko‘paytiring.

$$SAATa=a\times 418\times 10^{23}\times \frac{Bq}{a}$$

A^{2} hosil qilish uchun A va A ni ko'paytirish.

$$SA^{2}Ta=a\times 418\times 10^{23}\times \frac{Bq}{a}$$

23 daraja ko‘rsatkichini 10 ga hisoblang va 100000000000000000000000 ni qiymatni oling.

$$SA^{2}Ta=a\times 418\times 100000000000000000000000\times \frac{Bq}{a}$$

41800000000000000000000000 hosil qilish uchun 418 va 100000000000000000000000 ni ko'paytirish.

$$SA^{2}Ta=a\times 41800000000000000000000000\times \frac{Bq}{a}$$

a\times \frac{Bq}{a} ni yagona kasrga aylantiring.

$$SA^{2}Ta=\frac{aBq}{a}\times 41800000000000000000000000$$

Surat va maxrajdagi ikkala a ni qisqartiring.

$$SA^{2}Ta=Bq\times 41800000000000000000000000$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$Bq\times 41800000000000000000000000=SA^{2}Ta$$

Tenglama standart shaklda.

$$41800000000000000000000000qB=STaA^{2}$$

Ikki tarafini 41800000000000000000000000q ga bo‘ling.

$$\frac{41800000000000000000000000qB}{41800000000000000000000000q}=\frac{STaA^{2}}{41800000000000000000000000q}$$

41800000000000000000000000q ga bo'lish 41800000000000000000000000q ga ko'paytirishni bekor qiladi.

$$B=\frac{STaA^{2}}{41800000000000000000000000q}$$

B uchun yechish

$$\left\{\begin{matrix}B=\frac{STaA^{2}}{41800000000000000000000000q}\text{, }&q\neq 0\text{ and }A\neq 0\text{ and }T\neq 0\text{ and }a\neq 0\\B\in \mathrm{R}\text{, }&S=0\text{ and }q=0\text{ and }A\neq 0\text{ and }T\neq 0\text{ and }a\neq 0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tenglamaning ikkala tarafini ATa ga, AT,a ning eng kichik karralisiga ko‘paytiring.

$$SAATa=a\times 418\times 10^{23}\times \frac{Bq}{a}$$

A^{2} hosil qilish uchun A va A ni ko'paytirish.

$$SA^{2}Ta=a\times 418\times 10^{23}\times \frac{Bq}{a}$$

23 daraja ko‘rsatkichini 10 ga hisoblang va 100000000000000000000000 ni qiymatni oling.

$$SA^{2}Ta=a\times 418\times 100000000000000000000000\times \frac{Bq}{a}$$

41800000000000000000000000 hosil qilish uchun 418 va 100000000000000000000000 ni ko'paytirish.

$$SA^{2}Ta=a\times 41800000000000000000000000\times \frac{Bq}{a}$$

a\times \frac{Bq}{a} ni yagona kasrga aylantiring.

$$SA^{2}Ta=\frac{aBq}{a}\times 41800000000000000000000000$$

Surat va maxrajdagi ikkala a ni qisqartiring.

$$SA^{2}Ta=Bq\times 41800000000000000000000000$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$Bq\times 41800000000000000000000000=SA^{2}Ta$$

Tenglama standart shaklda.

$$41800000000000000000000000qB=STaA^{2}$$

Ikki tarafini 41800000000000000000000000q ga bo‘ling.

$$\frac{41800000000000000000000000qB}{41800000000000000000000000q}=\frac{STaA^{2}}{41800000000000000000000000q}$$

41800000000000000000000000q ga bo'lish 41800000000000000000000000q ga ko'paytirishni bekor qiladi.

$$B=\frac{STaA^{2}}{41800000000000000000000000q}$$

A uchun yechish (complex solution)

$$\left\{\begin{matrix}A=-200000000000S^{-\frac{1}{2}}T^{-\frac{1}{2}}a^{-\frac{1}{2}}\sqrt{B}\sqrt{1045q}\text{; }A=200000000000S^{-\frac{1}{2}}T^{-\frac{1}{2}}a^{-\frac{1}{2}}\sqrt{B}\sqrt{1045q}\text{, }&q\neq 0\text{ and }B\neq 0\text{ and }a\neq 0\text{ and }T\neq 0\text{ and }S\neq 0\\A\neq 0\text{, }&\left(q=0\text{ or }B=0\right)\text{ and }S=0\text{ and }a\neq 0\text{ and }T\neq 0\end{matrix}\right,$$