S=u+1/2at^2 eching

$$S = u + \frac { 1 } { 2 } a t ^ { 2 }$$

a uchun yechish

$$\left\{\begin{matrix}a=-\frac{2\left(u-S\right)}{t^{2}}\text{, }&t\neq 0\\a\in \mathrm{R}\text{, }&S=u\text{ and }t=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$u+\frac{1}{2}at^{2}=S$$

Ikkala tarafdan u ni ayirish.

$$\frac{1}{2}at^{2}=S-u$$

Tenglama standart shaklda.

$$\frac{t^{2}}{2}a=S-u$$

Ikki tarafini \frac{1}{2}t^{2} ga bo‘ling.

$$\frac{2\times \frac{t^{2}}{2}a}{t^{2}}=\frac{2\left(S-u\right)}{t^{2}}$$

\frac{1}{2}t^{2} ga bo'lish \frac{1}{2}t^{2} ga ko'paytirishni bekor qiladi.

$$a=\frac{2\left(S-u\right)}{t^{2}}$$

S uchun yechish

$$S=\frac{at^{2}}{2}+u$$