P(x)=3x^2-10x-6quadD(x)=x-3 eching

$$P ( x ) = 3 x ^ { 2 } - 10 x - 6 \quad D ( x ) = x - 3$$

D uchun yechish

$$D=\frac{x}{2}-\frac{11}{6}+\frac{1}{2x}$$

$$x\neq 0$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Ikkala tarafdan 3x^{2} ni ayirish.

$$-10x-6Dx=x-3-3x^{2}$$

10x ni ikki tarafga qo’shing.

$$-6Dx=x-3-3x^{2}+10x$$

11x ni olish uchun x va 10x ni birlashtirish.

$$-6Dx=11x-3-3x^{2}$$

Tenglama standart shaklda.

$$\left(-6x\right)D=-3x^{2}+11x-3$$

Ikki tarafini -6x ga bo‘ling.

$$\frac{\left(-6x\right)D}{-6x}=\frac{-3x^{2}+11x-3}{-6x}$$

-6x ga bo'lish -6x ga ko'paytirishni bekor qiladi.

$$D=\frac{-3x^{2}+11x-3}{-6x}$$

11x-3-3x^{2} ni -6x ga bo'lish.

$$D=\frac{x}{2}-\frac{11}{6}+\frac{1}{2x}$$

x uchun yechish (complex solution)

$$x=\frac{\sqrt{36D^{2}+132D+85}}{6}+D+\frac{11}{6}$$

$$x=-\frac{\sqrt{36D^{2}+132D+85}}{6}+D+\frac{11}{6}$$

x uchun yechish

$$x=\frac{\sqrt{36D^{2}+132D+85}}{6}+D+\frac{11}{6}$$

$$x=-\frac{\sqrt{36D^{2}+132D+85}}{6}+D+\frac{11}{6}\text{, }D\leq -\frac{17}{6}\text{ or }D\geq -\frac{5}{6}$$