P=a(1-cosθ) eching

$$P = a ( 1 - \cos \theta )$$

a uchun yechish

$$\left\{\begin{matrix}a=-\frac{P}{\cos(\theta )-1}\text{, }&\nexists n_{1}\in \mathrm{Z}\text{ : }\theta =2\pi n_{1}\\a\in \mathrm{R}\text{, }&P=0\text{ and }\exists n_{1}\in \mathrm{Z}\text{ : }\theta =2\pi n_{1}\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$a\left(1-\cos(\theta )\right)=P$$

a ga 1-\cos(\theta ) ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$a-a\cos(\theta )=P$$

a'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(1-\cos(\theta )\right)a=P$$

Tenglama standart shaklda.

$$\left(-\cos(\theta )+1\right)a=P$$

Ikki tarafini 1-\cos(\theta ) ga bo‘ling.

$$\frac{\left(-\cos(\theta )+1\right)a}{-\cos(\theta )+1}=\frac{P}{-\cos(\theta )+1}$$

1-\cos(\theta ) ga bo'lish 1-\cos(\theta ) ga ko'paytirishni bekor qiladi.

$$a=\frac{P}{-\cos(\theta )+1}$$

P uchun yechish

$$P=a\left(-\cos(\theta )+1\right)$$