P=sqrt{2Qh/100} eching

$$P = \sqrt { \frac { 2 Q h } { 100 } }$$

Q uchun yechish

$$\left\{\begin{matrix}Q=\frac{50P^{2}}{h}\text{, }&P\geq 0\text{ and }h\neq 0\\Q\in \mathrm{R}\text{, }&h=0\text{ and }P=0\end{matrix}\right,$$

Ildizli tenglamalarni yechish qadamlari

\frac{1}{50}Qh ni olish uchun 2Qh ni 100 ga bo‘ling.

$$P=\sqrt{\frac{1}{50}Qh}$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$\sqrt{\frac{1}{50}Qh}=P$$

Tenglamaning ikkala taraf kvadratini chiqarish.

$$\frac{h}{50}Q=P^{2}$$

Ikki tarafini \frac{1}{50}h ga bo‘ling.

$$\frac{50\times \frac{h}{50}Q}{h}=\frac{50P^{2}}{h}$$

\frac{1}{50}h ga bo'lish \frac{1}{50}h ga ko'paytirishni bekor qiladi.

$$Q=\frac{50P^{2}}{h}$$

P uchun yechish (complex solution)

$$P=\frac{\sqrt{2Qh}}{10}$$

Q uchun yechish (complex solution)

$$\left\{\begin{matrix}Q=\frac{50P^{2}}{h}\text{, }&h\neq 0\text{ and }\left(P=0\text{ or }arg(P)<\pi \right)\\Q\in \mathrm{C}\text{, }&P=0\text{ and }h=0\end{matrix}\right,$$

P uchun yechish

$$P=\frac{\sqrt{2Qh}}{10}$$

$$\left(h\geq 0\text{ and }Q\geq 0\right)\text{ or }\left(Q\leq 0\text{ and }h\leq 0\right)$$