H=25/21+8/7+4/3= eching

$$H = \frac { 25 } { 21 } + \frac { 8 } { 7 } + \frac { 4 } { 3 } =$$

H uchun yechish

$$H = \frac{11}{3} = 3\frac{2}{3} \approx 3,666666667$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

21 va 7 ning eng kichik umumiy karralisi 21 ga teng. \frac{25}{21} va \frac{8}{7} ni 21 maxraj bilan kasrlarga aylantirib oling.

$$H=\frac{25}{21}+\frac{24}{21}+\frac{4}{3}$$

\frac{25}{21} va \frac{24}{21} da bir xil maxraji bor, ularning suratini qo‘shish orqali qo‘shing.

$$H=\frac{25+24}{21}+\frac{4}{3}$$

49 olish uchun 25 va 24'ni qo'shing.

$$H=\frac{49}{21}+\frac{4}{3}$$

\frac{49}{21} ulushini 7 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$H=\frac{7}{3}+\frac{4}{3}$$

\frac{7}{3} va \frac{4}{3} da bir xil maxraji bor, ularning suratini qo‘shish orqali qo‘shing.

$$H=\frac{7+4}{3}$$

11 olish uchun 7 va 4'ni qo'shing.

$$H=\frac{11}{3}$$

H'ni tayinlash

$$H≔\frac{11}{3}$$