H=2/3(7+M)d eching

$$H = \frac { 2 } { 3 } ( 7 + M ) d$$

H uchun yechish

$$H=\frac{2d\left(M+7\right)}{3}$$

Yechim qadamlari

\frac{2}{3} ga 7+M ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$H=\left(\frac{14}{3}+\frac{2}{3}M\right)d$$

\frac{14}{3}+\frac{2}{3}M ga d ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$H=\frac{14}{3}d+\frac{2}{3}Md$$

M uchun yechish

$$\left\{\begin{matrix}M=\frac{3H}{2d}-7\text{, }&d\neq 0\\M\in \mathrm{R}\text{, }&H=0\text{ and }d=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

\frac{2}{3} ga 7+M ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$H=\left(\frac{14}{3}+\frac{2}{3}M\right)d$$

\frac{14}{3}+\frac{2}{3}M ga d ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$H=\frac{14}{3}d+\frac{2}{3}Md$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$\frac{14}{3}d+\frac{2}{3}Md=H$$

Ikkala tarafdan \frac{14}{3}d ni ayirish.

$$\frac{2}{3}Md=H-\frac{14}{3}d$$

Tenglama standart shaklda.

$$\frac{2d}{3}M=-\frac{14d}{3}+H$$

Ikki tarafini \frac{2}{3}d ga bo‘ling.

$$\frac{3\times \frac{2d}{3}M}{2d}=\frac{3\left(-\frac{14d}{3}+H\right)}{2d}$$

\frac{2}{3}d ga bo'lish \frac{2}{3}d ga ko'paytirishni bekor qiladi.

$$M=\frac{3\left(-\frac{14d}{3}+H\right)}{2d}$$

H-\frac{14d}{3} ni \frac{2}{3}d ga bo'lish.

$$M=\frac{3H}{2d}-7$$