Ed=28/10*7-10/33-28 eching

$$E d = \frac { 28 } { 10 } \times \frac { 7 - 10 } { 33 - 28 }$$

E uchun yechish

$$E=-\frac{42}{25d}$$

$$d\neq 0$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

\frac{28}{10} ulushini 2 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$Ed=\frac{14}{5}\times \frac{7-10}{33-28}$$

-3 olish uchun 7 dan 10 ni ayirish.

$$Ed=\frac{14}{5}\times \frac{-3}{33-28}$$

5 olish uchun 33 dan 28 ni ayirish.

$$Ed=\frac{14}{5}\times \frac{-3}{5}$$

\frac{-3}{5} kasri manfiy belgini olib tashlash bilan -\frac{3}{5} sifatida qayta yozilishi mumkin.

$$Ed=\frac{14}{5}\left(-\frac{3}{5}\right)$$

-\frac{42}{25} hosil qilish uchun \frac{14}{5} va -\frac{3}{5} ni ko'paytirish.

$$Ed=-\frac{42}{25}$$

Tenglama standart shaklda.

$$dE=-\frac{42}{25}$$

Ikki tarafini d ga bo‘ling.

$$\frac{dE}{d}=-\frac{\frac{42}{25}}{d}$$

d ga bo'lish d ga ko'paytirishni bekor qiladi.

$$E=-\frac{\frac{42}{25}}{d}$$

-\frac{42}{25} ni d ga bo'lish.

$$E=-\frac{42}{25d}$$

d uchun yechish

$$d=-\frac{42}{25E}$$

$$E\neq 0$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

\frac{28}{10} ulushini 2 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$Ed=\frac{14}{5}\times \frac{7-10}{33-28}$$

-3 olish uchun 7 dan 10 ni ayirish.

$$Ed=\frac{14}{5}\times \frac{-3}{33-28}$$

5 olish uchun 33 dan 28 ni ayirish.

$$Ed=\frac{14}{5}\times \frac{-3}{5}$$

\frac{-3}{5} kasri manfiy belgini olib tashlash bilan -\frac{3}{5} sifatida qayta yozilishi mumkin.

$$Ed=\frac{14}{5}\left(-\frac{3}{5}\right)$$

-\frac{42}{25} hosil qilish uchun \frac{14}{5} va -\frac{3}{5} ni ko'paytirish.

$$Ed=-\frac{42}{25}$$

Ikki tarafini E ga bo‘ling.

$$\frac{Ed}{E}=-\frac{\frac{42}{25}}{E}$$

E ga bo'lish E ga ko'paytirishni bekor qiladi.

$$d=-\frac{\frac{42}{25}}{E}$$

-\frac{42}{25} ni E ga bo'lish.

$$d=-\frac{42}{25E}$$