DT=sqrt{(1-sqrt{2})^2} eching

$$D T = \sqrt { ( 1 - \sqrt { 2 } ) ^ { 2 } }$$

D uchun yechish

$$D=\frac{\sqrt{2}-1}{T}$$

$$T\neq 0$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

\left(a-b\right)^{2}=a^{2}-2ab+b^{2} binom teoremasini \left(1-\sqrt{2}\right)^{2} kengaytirilishi uchun ishlating.

$$DT=\sqrt{1-2\sqrt{2}+\left(\sqrt{2}\right)^{2}}$$

\sqrt{2} kvadrati – 2.

$$DT=\sqrt{1-2\sqrt{2}+2}$$

3 olish uchun 1 va 2'ni qo'shing.

$$DT=\sqrt{3-2\sqrt{2}}$$

Tenglama standart shaklda.

$$TD=\sqrt{3-2\sqrt{2}}$$

Ikki tarafini T ga bo‘ling.

$$\frac{TD}{T}=\frac{\sqrt{2}-1}{T}$$

T ga bo'lish T ga ko'paytirishni bekor qiladi.

$$D=\frac{\sqrt{2}-1}{T}$$

T uchun yechish

$$T=\frac{\sqrt{2}-1}{D}$$

$$D\neq 0$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

\left(a-b\right)^{2}=a^{2}-2ab+b^{2} binom teoremasini \left(1-\sqrt{2}\right)^{2} kengaytirilishi uchun ishlating.

$$DT=\sqrt{1-2\sqrt{2}+\left(\sqrt{2}\right)^{2}}$$

\sqrt{2} kvadrati – 2.

$$DT=\sqrt{1-2\sqrt{2}+2}$$

3 olish uchun 1 va 2'ni qo'shing.

$$DT=\sqrt{3-2\sqrt{2}}$$

Ikki tarafini D ga bo‘ling.

$$\frac{DT}{D}=\frac{\sqrt{2}-1}{D}$$

D ga bo'lish D ga ko'paytirishni bekor qiladi.

$$T=\frac{\sqrt{2}-1}{D}$$