DquadD= eching

$$D \quad D =$$

D ga nisbatan hosilani topish

$$2D$$

Koʻpaytma uchun derivativ qoidasidan foydalanish qadamlari

Har qanday ikki differensial funksiya uchun, ikki funksiya koʻpaytmasining hosilasi birinchi funksiya marotabasi, ikkinchi plyus hosilasi ikkinchi funksiya marotabasi birinchining hosilasidir.

$$D^{1}\frac{\mathrm{d}}{\mathrm{d}D}(D^{1})+D^{1}\frac{\mathrm{d}}{\mathrm{d}D}(D^{1})$$

Polinomialning hosilasi bu uning shartlari hosilasining yig‘indisiga teng. Konstant shartning hosilasi 0. ax^{n} ning hosilasi nax^{n-1}.

$$D^{1}D^{1-1}+D^{1}D^{1-1}$$

Qisqartirish.

$$D^{1}D^{0}+D^{1}D^{0}$$

Ayni daraja ko'rsatkichlarini ko'paytirish uchun ularning darajalarini qo'shing.

$$D^{1}+D^{1}$$

O'xshash hadlarni birlashtirish.

$$\left(1+1\right)D^{1}$$

1 ni 1 ga qo'shish.

$$2D^{1}$$

Har qanday t sharti uchun t^{1}=t.

$$2D$$

Baholash

$$D^{2}$$

Yechim qadamlari

D^{2} hosil qilish uchun D va D ni ko'paytirish.

$$D^{2}$$