A uchun yechish (complex solution)
\left\{\begin{matrix}A=\frac{C_{p}}{Th_{1}t\Delta }\text{, }&T\neq 0\text{ and }\Delta \neq 0\text{ and }t\neq 0\text{ and }h_{1}\neq 0\\A\in \mathrm{C}\text{, }&\left(T=0\text{ or }\Delta =0\text{ or }t=0\text{ or }h_{1}=0\right)\text{ and }C_{p}=0\end{matrix}\right,
A uchun yechish
\left\{\begin{matrix}A=\frac{C_{p}}{Th_{1}t\Delta }\text{, }&T\neq 0\text{ and }\Delta \neq 0\text{ and }t\neq 0\text{ and }h_{1}\neq 0\\A\in \mathrm{R}\text{, }&\left(T=0\text{ or }\Delta =0\text{ or }t=0\text{ or }h_{1}=0\right)\text{ and }C_{p}=0\end{matrix}\right,
C_p uchun yechish
C_{p}=ATh_{1}t\Delta
Baham ko'rish
Klipbordga nusxa olish
h_{1}At\Delta T=C_{p}
Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.
Th_{1}t\Delta A=C_{p}
Tenglama standart shaklda.
\frac{Th_{1}t\Delta A}{Th_{1}t\Delta }=\frac{C_{p}}{Th_{1}t\Delta }
Ikki tarafini h_{1}t\Delta T ga bo‘ling.
A=\frac{C_{p}}{Th_{1}t\Delta }
h_{1}t\Delta T ga bo'lish h_{1}t\Delta T ga ko'paytirishni bekor qiladi.
h_{1}At\Delta T=C_{p}
Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.
Th_{1}t\Delta A=C_{p}
Tenglama standart shaklda.
\frac{Th_{1}t\Delta A}{Th_{1}t\Delta }=\frac{C_{p}}{Th_{1}t\Delta }
Ikki tarafini h_{1}t\Delta T ga bo‘ling.
A=\frac{C_{p}}{Th_{1}t\Delta }
h_{1}t\Delta T ga bo'lish h_{1}t\Delta T ga ko'paytirishni bekor qiladi.
Misollar
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