C=b(1+1/m) eching

$$C = b ( 1 + \frac { 1 } { m } )$$

b uchun yechish

$$\left\{\begin{matrix}b=\frac{Cm}{m+1}\text{, }&m\neq -1\text{ and }m\neq 0\\b\in \mathrm{R}\text{, }&m=-1\text{ and }C=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tenglamaning ikkala tarafini m ga ko'paytirish.

$$Cm=b\left(1+\frac{1}{m}\right)m$$

Ifodalarni qo‘shish yoki ayirish uchun ularni yoyib, maxrajlarini bir xil qiling. 1 ni \frac{m}{m} marotabaga ko'paytirish.

$$Cm=b\left(\frac{m}{m}+\frac{1}{m}\right)m$$

\frac{m}{m} va \frac{1}{m} da bir xil maxraji bor, ularning suratini qo‘shish orqali qo‘shing.

$$Cm=b\times \frac{m+1}{m}m$$

b\times \frac{m+1}{m} ni yagona kasrga aylantiring.

$$Cm=\frac{b\left(m+1\right)}{m}m$$

\frac{b\left(m+1\right)}{m}m ni yagona kasrga aylantiring.

$$Cm=\frac{b\left(m+1\right)m}{m}$$

Surat va maxrajdagi ikkala m ni qisqartiring.

$$Cm=b\left(m+1\right)$$

b ga m+1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$Cm=bm+b$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$bm+b=Cm$$

b'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(m+1\right)b=Cm$$

Ikki tarafini m+1 ga bo‘ling.

$$\frac{\left(m+1\right)b}{m+1}=\frac{Cm}{m+1}$$

m+1 ga bo'lish m+1 ga ko'paytirishni bekor qiladi.

$$b=\frac{Cm}{m+1}$$

C uchun yechish

$$C=b+\frac{b}{m}$$

$$m\neq 0$$