Ap^2=s^2+12^2 eching

$$A p ^ { 2 } = s ^ { 2 } + 12 ^ { 2 }$$

A uchun yechish (complex solution)

$$\left\{\begin{matrix}A=\frac{s^{2}+144}{p^{2}}\text{, }&p\neq 0\\A\in \mathrm{C}\text{, }&\left(s=-12i\text{ or }s=12i\right)\text{ and }p=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

2 daraja ko‘rsatkichini 12 ga hisoblang va 144 ni qiymatni oling.

$$Ap^{2}=s^{2}+144$$

Tenglama standart shaklda.

$$p^{2}A=s^{2}+144$$

Ikki tarafini p^{2} ga bo‘ling.

$$\frac{p^{2}A}{p^{2}}=\frac{s^{2}+144}{p^{2}}$$

p^{2} ga bo'lish p^{2} ga ko'paytirishni bekor qiladi.

$$A=\frac{s^{2}+144}{p^{2}}$$

A uchun yechish

$$A=\frac{s^{2}+144}{p^{2}}$$

$$p\neq 0$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

2 daraja ko‘rsatkichini 12 ga hisoblang va 144 ni qiymatni oling.

$$Ap^{2}=s^{2}+144$$

Tenglama standart shaklda.

$$p^{2}A=s^{2}+144$$

Ikki tarafini p^{2} ga bo‘ling.

$$\frac{p^{2}A}{p^{2}}=\frac{s^{2}+144}{p^{2}}$$

p^{2} ga bo'lish p^{2} ga ko'paytirishni bekor qiladi.

$$A=\frac{s^{2}+144}{p^{2}}$$

p uchun yechish (complex solution)

$$\left\{\begin{matrix}p=-A^{-\frac{1}{2}}\sqrt{s^{2}+144}\text{; }p=A^{-\frac{1}{2}}\sqrt{s^{2}+144}\text{, }&A\neq 0\\p\in \mathrm{C}\text{, }&\left(s=-12i\text{ or }s=12i\right)\text{ and }A=0\end{matrix}\right,$$

p uchun yechish

$$p=\sqrt{\frac{s^{2}+144}{A}}$$

$$p=-\sqrt{\frac{s^{2}+144}{A}}\text{, }A>0$$