Asosiy tarkibga oʻtish
A uchun yechish
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P uchun yechish
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Veb-qidiruvdagi o'xshash muammolar

Baham ko'rish

A=P\left(1+\frac{1}{100}i\right)^{2}
\frac{1}{100}i ni olish uchun i ni 100 ga bo‘ling.
A=P\left(\frac{9999}{10000}+\frac{1}{50}i\right)
2 daraja ko‘rsatkichini 1+\frac{1}{100}i ga hisoblang va \frac{9999}{10000}+\frac{1}{50}i ni qiymatni oling.
A=P\left(1+\frac{1}{100}i\right)^{2}
\frac{1}{100}i ni olish uchun i ni 100 ga bo‘ling.
A=P\left(\frac{9999}{10000}+\frac{1}{50}i\right)
2 daraja ko‘rsatkichini 1+\frac{1}{100}i ga hisoblang va \frac{9999}{10000}+\frac{1}{50}i ni qiymatni oling.
P\left(\frac{9999}{10000}+\frac{1}{50}i\right)=A
Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.
\left(\frac{9999}{10000}+\frac{1}{50}i\right)P=A
Tenglama standart shaklda.
\frac{\left(\frac{9999}{10000}+\frac{1}{50}i\right)P}{\frac{9999}{10000}+\frac{1}{50}i}=\frac{A}{\frac{9999}{10000}+\frac{1}{50}i}
Ikki tarafini \frac{9999}{10000}+\frac{1}{50}i ga bo‘ling.
P=\frac{A}{\frac{9999}{10000}+\frac{1}{50}i}
\frac{9999}{10000}+\frac{1}{50}i ga bo'lish \frac{9999}{10000}+\frac{1}{50}i ga ko'paytirishni bekor qiladi.
P=\left(\frac{99990000}{100020001}-\frac{2000000}{100020001}i\right)A
A ni \frac{9999}{10000}+\frac{1}{50}i ga bo'lish.