A=1/2h(b+c) eching

$$A = 1 / 2 h ( b + c )$$

b uchun yechish

$$\left\{\begin{matrix}b=-c+\frac{2A}{h}\text{, }&h\neq 0\\b\in \mathrm{R}\text{, }&A=0\text{ and }h=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

\frac{1}{2}h ga b+c ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$A=\frac{1}{2}hb+\frac{1}{2}hc$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$\frac{1}{2}hb+\frac{1}{2}hc=A$$

Ikkala tarafdan \frac{1}{2}hc ni ayirish.

$$\frac{1}{2}hb=A-\frac{1}{2}hc$$

Tenglama standart shaklda.

$$\frac{h}{2}b=-\frac{ch}{2}+A$$

Ikki tarafini \frac{1}{2}h ga bo‘ling.

$$\frac{2\times \frac{h}{2}b}{h}=\frac{2\left(-\frac{ch}{2}+A\right)}{h}$$

\frac{1}{2}h ga bo'lish \frac{1}{2}h ga ko'paytirishni bekor qiladi.

$$b=\frac{2\left(-\frac{ch}{2}+A\right)}{h}$$

A-\frac{ch}{2} ni \frac{1}{2}h ga bo'lish.

$$b=-c+\frac{2A}{h}$$

A uchun yechish

$$A=\frac{h\left(b+c\right)}{2}$$