A=piAB eching

$$A = \pi A B$$

A uchun yechish

$$\left\{\begin{matrix}\\A=0\text{, }&\text{unconditionally}\\A\in \mathrm{R}\text{, }&B=\frac{1}{\pi }\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Ikkala tarafdan \pi AB ni ayirish.

$$A-\pi AB=0$$

Shartlarni qayta saralash.

$$-\pi AB+A=0$$

A'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(-\pi B+1\right)A=0$$

Tenglama standart shaklda.

$$\left(1-\pi B\right)A=0$$

0 ni 1-\pi B ga bo'lish.

$$A=0$$

B uchun yechish

$$\left\{\begin{matrix}\\B=\frac{1}{\pi }\text{, }&\text{unconditionally}\\B\in \mathrm{R}\text{, }&A=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$\pi AB=A$$

Ikki tarafini \pi A ga bo‘ling.

$$\frac{\pi AB}{\pi A}=\frac{A}{\pi A}$$

\pi A ga bo'lish \pi A ga ko'paytirishni bekor qiladi.

$$B=\frac{A}{\pi A}$$

A ni \pi A ga bo'lish.

$$B=\frac{1}{\pi }$$