9-2(x+4)-10(25-x+4)=5-3x-4(x+1) eching

$$9-2(x+4)-10(25-x+4)=5-3x-4(x+1)$$

x uchun yechish

$$x = \frac{58}{3} = 19\frac{1}{3} \approx 19,333333333$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

-2 ga x+4 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$9-2x-8-10\left(25-x+4\right)=5-3x-4\left(x+1\right)$$

1 olish uchun 9 dan 8 ni ayirish.

$$1-2x-10\left(25-x+4\right)=5-3x-4\left(x+1\right)$$

29 olish uchun 25 va 4'ni qo'shing.

$$1-2x-10\left(29-x\right)=5-3x-4\left(x+1\right)$$

-10 ga 29-x ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$1-2x-290+10x=5-3x-4\left(x+1\right)$$

-289 olish uchun 1 dan 290 ni ayirish.

$$-289-2x+10x=5-3x-4\left(x+1\right)$$

8x ni olish uchun -2x va 10x ni birlashtirish.

$$-289+8x=5-3x-4\left(x+1\right)$$

-4 ga x+1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$-289+8x=5-3x-4x-4$$

-7x ni olish uchun -3x va -4x ni birlashtirish.

$$-289+8x=5-7x-4$$

1 olish uchun 5 dan 4 ni ayirish.

$$-289+8x=1-7x$$

7x ni ikki tarafga qo’shing.

$$-289+8x+7x=1$$

15x ni olish uchun 8x va 7x ni birlashtirish.

$$-289+15x=1$$

289 ni ikki tarafga qo’shing.

$$15x=1+289$$

290 olish uchun 1 va 289'ni qo'shing.

$$15x=290$$

Ikki tarafini 15 ga bo‘ling.

$$x=\frac{290}{15}$$

\frac{290}{15} ulushini 5 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$x=\frac{58}{3}$$