9z^2+95z+10 eching

$$9 z ^ { 2 } + 95 z + 10$$

Omil

$$9\left(z-\frac{-\sqrt{8665}-95}{18}\right)\left(z-\frac{\sqrt{8665}-95}{18}\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$9z^{2}+95z+10=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$z=\frac{-95±\sqrt{95^{2}-4\times 9\times 10}}{2\times 9}$$

95 kvadratini chiqarish.

$$z=\frac{-95±\sqrt{9025-4\times 9\times 10}}{2\times 9}$$

-4 ni 9 marotabaga ko'paytirish.

$$z=\frac{-95±\sqrt{9025-36\times 10}}{2\times 9}$$

-36 ni 10 marotabaga ko'paytirish.

$$z=\frac{-95±\sqrt{9025-360}}{2\times 9}$$

9025 ni -360 ga qo'shish.

$$z=\frac{-95±\sqrt{8665}}{2\times 9}$$

2 ni 9 marotabaga ko'paytirish.

$$z=\frac{-95±\sqrt{8665}}{18}$$

z=\frac{-95±\sqrt{8665}}{18} tenglamasini yeching, bunda ± musbat. -95 ni \sqrt{8665} ga qo'shish.

$$z=\frac{\sqrt{8665}-95}{18}$$

z=\frac{-95±\sqrt{8665}}{18} tenglamasini yeching, bunda ± manfiy. -95 dan \sqrt{8665} ni ayirish.

$$z=\frac{-\sqrt{8665}-95}{18}$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun \frac{-95+\sqrt{8665}}{18} ga va x_{2} uchun \frac{-95-\sqrt{8665}}{18} ga bo‘ling.

$$9z^{2}+95z+10=9\left(z-\frac{\sqrt{8665}-95}{18}\right)\left(z-\frac{-\sqrt{8665}-95}{18}\right)$$

Baholash

$$9z^{2}+95z+10$$