9x^2+9x-72 eching

$$9 x ^ { 2 } + 9 x - 72$$

Omil

$$9\left(x-\frac{-\sqrt{33}-1}{2}\right)\left(x-\frac{\sqrt{33}-1}{2}\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$9x^{2}+9x-72=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$x=\frac{-9±\sqrt{9^{2}-4\times 9\left(-72\right)}}{2\times 9}$$

9 kvadratini chiqarish.

$$x=\frac{-9±\sqrt{81-4\times 9\left(-72\right)}}{2\times 9}$$

-4 ni 9 marotabaga ko'paytirish.

$$x=\frac{-9±\sqrt{81-36\left(-72\right)}}{2\times 9}$$

-36 ni -72 marotabaga ko'paytirish.

$$x=\frac{-9±\sqrt{81+2592}}{2\times 9}$$

81 ni 2592 ga qo'shish.

$$x=\frac{-9±\sqrt{2673}}{2\times 9}$$

2673 ning kvadrat ildizini chiqarish.

$$x=\frac{-9±9\sqrt{33}}{2\times 9}$$

2 ni 9 marotabaga ko'paytirish.

$$x=\frac{-9±9\sqrt{33}}{18}$$

x=\frac{-9±9\sqrt{33}}{18} tenglamasini yeching, bunda ± musbat. -9 ni 9\sqrt{33} ga qo'shish.

$$x=\frac{9\sqrt{33}-9}{18}$$

-9+9\sqrt{33} ni 18 ga bo'lish.

$$x=\frac{\sqrt{33}-1}{2}$$

x=\frac{-9±9\sqrt{33}}{18} tenglamasini yeching, bunda ± manfiy. -9 dan 9\sqrt{33} ni ayirish.

$$x=\frac{-9\sqrt{33}-9}{18}$$

-9-9\sqrt{33} ni 18 ga bo'lish.

$$x=\frac{-\sqrt{33}-1}{2}$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun \frac{-1+\sqrt{33}}{2} ga va x_{2} uchun \frac{-1-\sqrt{33}}{2} ga bo‘ling.

$$9x^{2}+9x-72=9\left(x-\frac{\sqrt{33}-1}{2}\right)\left(x-\frac{-\sqrt{33}-1}{2}\right)$$

Baholash

$$9\left(x^{2}+x-8\right)$$