9x^2+1x-97 eching

$$9 x ^ { 2 } + 1 x - 97$$

Omil

$$9\left(x-\frac{-\sqrt{3493}-1}{18}\right)\left(x-\frac{\sqrt{3493}-1}{18}\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$9x^{2}+x-97=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$x=\frac{-1±\sqrt{1^{2}-4\times 9\left(-97\right)}}{2\times 9}$$

1 kvadratini chiqarish.

$$x=\frac{-1±\sqrt{1-4\times 9\left(-97\right)}}{2\times 9}$$

-4 ni 9 marotabaga ko'paytirish.

$$x=\frac{-1±\sqrt{1-36\left(-97\right)}}{2\times 9}$$

-36 ni -97 marotabaga ko'paytirish.

$$x=\frac{-1±\sqrt{1+3492}}{2\times 9}$$

1 ni 3492 ga qo'shish.

$$x=\frac{-1±\sqrt{3493}}{2\times 9}$$

2 ni 9 marotabaga ko'paytirish.

$$x=\frac{-1±\sqrt{3493}}{18}$$

x=\frac{-1±\sqrt{3493}}{18} tenglamasini yeching, bunda ± musbat. -1 ni \sqrt{3493} ga qo'shish.

$$x=\frac{\sqrt{3493}-1}{18}$$

x=\frac{-1±\sqrt{3493}}{18} tenglamasini yeching, bunda ± manfiy. -1 dan \sqrt{3493} ni ayirish.

$$x=\frac{-\sqrt{3493}-1}{18}$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun \frac{-1+\sqrt{3493}}{18} ga va x_{2} uchun \frac{-1-\sqrt{3493}}{18} ga bo‘ling.

$$9x^{2}+x-97=9\left(x-\frac{\sqrt{3493}-1}{18}\right)\left(x-\frac{-\sqrt{3493}-1}{18}\right)$$

Baholash

$$9x^{2}+x-97$$