9x=x^2= eching

$$9 x = x ^ { 2 } =$$

x uchun yechish

$$x=9$$

$$x=0$$

Faktorlash qadamlari

Ikkala tarafdan x^{2} ni ayirish.

$$9x-x^{2}=0$$

x omili.

$$x\left(9-x\right)=0$$

Tenglamani yechish uchun x=0 va 9-x=0 ni yeching.

$$x=0 x=9$$

Kvadrat tenglamalaridan foydalanish qoidalari

Ikkala tarafdan x^{2} ni ayirish.

$$9x-x^{2}=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$-x^{2}+9x=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} -1 ni a, 9 ni b va 0 ni c bilan almashtiring.

$$x=\frac{-9±\sqrt{9^{2}}}{2\left(-1\right)}$$

9^{2} ning kvadrat ildizini chiqarish.

$$x=\frac{-9±9}{2\left(-1\right)}$$

2 ni -1 marotabaga ko'paytirish.

$$x=\frac{-9±9}{-2}$$

x=\frac{-9±9}{-2} tenglamasini yeching, bunda ± musbat. -9 ni 9 ga qo'shish.

$$x=\frac{0}{-2}$$

0 ni -2 ga bo'lish.

$$x=0$$

x=\frac{-9±9}{-2} tenglamasini yeching, bunda ± manfiy. -9 dan 9 ni ayirish.

$$x=-\frac{18}{-2}$$

-18 ni -2 ga bo'lish.

$$x=9$$

Tenglama yechildi.

$$x=0 x=9$$

Kvadratni yakunlash bo'yicha qadamlar

Ikkala tarafdan x^{2} ni ayirish.

$$9x-x^{2}=0$$

Bu kabi kvadrat tenglamalarni kvadratni yakunlab yechish mumkin. Kvadratni yechish uchun tenglama avval ushbu shaklda bo'lishi shart: x^{2}+bx=c.

$$-x^{2}+9x=0$$

Ikki tarafini -1 ga bo‘ling.

$$\frac{-x^{2}+9x}{-1}=\frac{0}{-1}$$

-1 ga bo'lish -1 ga ko'paytirishni bekor qiladi.

$$x^{2}+\frac{9}{-1}x=\frac{0}{-1}$$

9 ni -1 ga bo'lish.

$$x^{2}-9x=\frac{0}{-1}$$

0 ni -1 ga bo'lish.

$$x^{2}-9x=0$$

-9 ni bo‘lish, x shartining koeffitsienti, 2 ga -\frac{9}{2} olish uchun. Keyin, -\frac{9}{2} ning kvadratini tenglamaning ikkala tarafiga qo‘shing. Ushbu qadam tenglamaning chap qismini mukammal kvadrat sifatida hosil qiladi.

$$x^{2}-9x+\left(-\frac{9}{2}\right)^{2}=\left(-\frac{9}{2}\right)^{2}$$

Kasrning ham suratini, ham maxrajini kvadratga ko'paytirib -\frac{9}{2} kvadratini chiqarish.

$$x^{2}-9x+\frac{81}{4}=\frac{81}{4}$$

x^{2}-9x+\frac{81}{4} omili. Odatda, x^{2}+bx+c mukammal kvadrat bo'lsa, u doimo \left(x+\frac{b}{2}\right)^{2} omil sifatida bo'lishi mumkin.

$$\left(x-\frac{9}{2}\right)^{2}=\frac{81}{4}$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$\sqrt{\left(x-\frac{9}{2}\right)^{2}}=\sqrt{\frac{81}{4}}$$

Qisqartirish.

$$x-\frac{9}{2}=\frac{9}{2} x-\frac{9}{2}=-\frac{9}{2}$$

\frac{9}{2} ni tenglamaning ikkala tarafiga qo'shish.

$$x=9 x=0$$