9*(-{left(2/3right)}^2-12*(-2/3)+3 eching

$$9 \times (- { \left( \frac{ 2 }{ 3 } \right) }^{ 2 } -12 \times (- \frac{ 2 }{ 3 } )+3$$

Baholash

$$95$$

Yechim qadamlari

2 daraja ko‘rsatkichini \frac{2}{3} ga hisoblang va \frac{4}{9} ni qiymatni oling.

$$9\left(-\frac{4}{9}-12\left(-\frac{2}{3}\right)+3\right)$$

12\left(-\frac{2}{3}\right) ni yagona kasrga aylantiring.

$$9\left(-\frac{4}{9}-\frac{12\left(-2\right)}{3}+3\right)$$

-24 hosil qilish uchun 12 va -2 ni ko'paytirish.

$$9\left(-\frac{4}{9}-\frac{-24}{3}+3\right)$$

-8 ni olish uchun -24 ni 3 ga bo‘ling.

$$9\left(-\frac{4}{9}-\left(-8\right)+3\right)$$

-8 ning teskarisi 8 ga teng.

$$9\left(-\frac{4}{9}+8+3\right)$$

8 ni \frac{72}{9} kasrga o‘giring.

$$9\left(-\frac{4}{9}+\frac{72}{9}+3\right)$$

-\frac{4}{9} va \frac{72}{9} da bir xil maxraji bor, ularning suratini qo‘shish orqali qo‘shing.

$$9\left(\frac{-4+72}{9}+3\right)$$

68 olish uchun -4 va 72'ni qo'shing.

$$9\left(\frac{68}{9}+3\right)$$

3 ni \frac{27}{9} kasrga o‘giring.

$$9\left(\frac{68}{9}+\frac{27}{9}\right)$$

\frac{68}{9} va \frac{27}{9} da bir xil maxraji bor, ularning suratini qo‘shish orqali qo‘shing.

$$9\times \frac{68+27}{9}$$

95 olish uchun 68 va 27'ni qo'shing.

$$9\times \frac{95}{9}$$

9 va 9 ni qisqartiring.

$$95$$

Omil

$$5\times 19$$