899*10^9(6*10^-9(-3*10^-9)/(4)^2) eching

$$899 \times 10 ^ { 9 } ( \frac { 6 \times 10 ^ { - 9 } ( - 3 \times 10 ^ { - 9 } ) } { ( 4 ) ^ { 2 } } )$$

Baholash

$$-\frac{8091}{8000000000}=-0,000001011$$

Yechim qadamlari

Ayni asosning daraja ko‘rsatkichlarini ko‘paytirish uchun ularning darajalarini qo‘shing. -9 va -9 ni qo‘shib, -18 ni oling.

$$899\times 10^{9}\times \frac{6\times 10^{-18}\left(-3\right)}{4^{2}}$$

9 daraja ko‘rsatkichini 10 ga hisoblang va 1000000000 ni qiymatni oling.

$$899\times 1000000000\times \frac{6\times 10^{-18}\left(-3\right)}{4^{2}}$$

899000000000 hosil qilish uchun 899 va 1000000000 ni ko'paytirish.

$$899000000000\times \frac{6\times 10^{-18}\left(-3\right)}{4^{2}}$$

-18 daraja ko‘rsatkichini 10 ga hisoblang va \frac{1}{1000000000000000000} ni qiymatni oling.

$$899000000000\times \frac{6\times \frac{1}{1000000000000000000}\left(-3\right)}{4^{2}}$$

\frac{3}{500000000000000000} hosil qilish uchun 6 va \frac{1}{1000000000000000000} ni ko'paytirish.

$$899000000000\times \frac{\frac{3}{500000000000000000}\left(-3\right)}{4^{2}}$$

-\frac{9}{500000000000000000} hosil qilish uchun \frac{3}{500000000000000000} va -3 ni ko'paytirish.

$$899000000000\times \frac{-\frac{9}{500000000000000000}}{4^{2}}$$

2 daraja ko‘rsatkichini 4 ga hisoblang va 16 ni qiymatni oling.

$$899000000000\times \frac{-\frac{9}{500000000000000000}}{16}$$

\frac{-\frac{9}{500000000000000000}}{16} ni yagona kasrga aylantiring.

$$899000000000\times \frac{-9}{500000000000000000\times 16}$$

8000000000000000000 hosil qilish uchun 500000000000000000 va 16 ni ko'paytirish.

$$899000000000\times \frac{-9}{8000000000000000000}$$

\frac{-9}{8000000000000000000} kasri manfiy belgini olib tashlash bilan -\frac{9}{8000000000000000000} sifatida qayta yozilishi mumkin.

$$899000000000\left(-\frac{9}{8000000000000000000}\right)$$

-\frac{8091}{8000000000} hosil qilish uchun 899000000000 va -\frac{9}{8000000000000000000} ni ko'paytirish.

$$-\frac{8091}{8000000000}$$

Omil

$$-\frac{8091}{8000000000} = -1,011375 \times 10^{-6}$$