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x^{2}\leq \frac{16}{81}
Ikki tarafini 81 ga bo‘ling. 81 musbat bo‘lgani uchun, tengsizlik yo‘nalishi o‘zgarmaydi.
x^{2}\leq \left(\frac{4}{9}\right)^{2}
\frac{16}{81} ning kvadrat ildizini hisoblab, \frac{4}{9} natijaga ega bo‘ling. \frac{16}{81} ni \left(\frac{4}{9}\right)^{2} sifatida qaytadan yozish.
|x|\leq \frac{4}{9}
Tengsizlikda |x|\leq \frac{4}{9} bor.
x\in \begin{bmatrix}-\frac{4}{9},\frac{4}{9}\end{bmatrix}
|x|\leq \frac{4}{9} ni x\in \left[-\frac{4}{9},\frac{4}{9}\right] sifatida qaytadan yozish.