81a^10-24a eching

$$81 a ^ { 10 } - 24 a$$

Omil

$$3a\left(3a^{3}-2\right)\left(9a^{6}+6a^{3}+4\right)$$

Yechim qadamlari

3 omili.

$$3\left(27a^{10}-8a\right)$$

Hisoblang: 27a^{10}-8a. a omili.

$$a\left(27a^{9}-8\right)$$

Hisoblang: 27a^{9}-8. 27a^{9}-8 ni \left(3a^{3}\right)^{3}-2^{3} sifatida qaytadan yozish. Kublarning farqini ushbu formula bilan hisoblash mumkin: p^{3}-q^{3}=\left(p-q\right)\left(p^{2}+pq+q^{2}\right).

$$\left(3a^{3}-2\right)\left(9a^{6}+6a^{3}+4\right)$$

Toʻliq ajratilgan ifodani qaytadan yozing. Quyidagi koʻphadlar faktorlanmagan, ularda hech qanday ratsional ildizlar topilmadi: 3a^{3}-2,9a^{6}+6a^{3}+4.

$$3a\left(3a^{3}-2\right)\left(9a^{6}+6a^{3}+4\right)$$

Baholash

$$81a^{10}-24a$$