800*(1+x/10)*(1-x/10)=800-32 eching

$$800 \times ( 1 + \frac { x } { 10 } ) \times ( 1 - \frac { x } { 10 } ) = 800 - 32$$

x uchun yechish

$$x=2$$

$$x=-2$$

Kvadrat ildizini topish bo'yicha qadamlar

Tenglamaning ikkala tarafini 10 ga ko'paytirish.

$$8000\left(1+\frac{x}{10}\right)\left(1-\frac{x}{10}\right)=8000-320$$

8000 ga 1+\frac{x}{10} ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$\left(8000+8000\times \frac{x}{10}\right)\left(1-\frac{x}{10}\right)=8000-320$$

8000 va 10 ichida eng katta umumiy 10 faktorini bekor qiling.

$$\left(8000+800x\right)\left(1-\frac{x}{10}\right)=8000-320$$

8000+800x ifodaning har bir elementini 1-\frac{x}{10} ifodaning har bir elementiga ko‘paytirish orqali taqsimot qonuni xususiyatlarini qo‘llash mumkin.

$$8000+8000\left(-\frac{x}{10}\right)+800x+800x\left(-\frac{x}{10}\right)=8000-320$$

8000 va 10 ichida eng katta umumiy 10 faktorini bekor qiling.

$$8000-800x+800x+800x\left(-\frac{x}{10}\right)=8000-320$$

0 ni olish uchun -800x va 800x ni birlashtirish.

$$8000+800x\left(-\frac{x}{10}\right)=8000-320$$

800 va 10 ichida eng katta umumiy 10 faktorini bekor qiling.

$$8000-80xx=8000-320$$

x^{2} hosil qilish uchun x va x ni ko'paytirish.

$$8000-80x^{2}=8000-320$$

7680 olish uchun 8000 dan 320 ni ayirish.

$$8000-80x^{2}=7680$$

Ikkala tarafdan 8000 ni ayirish.

$$-80x^{2}=7680-8000$$

-320 olish uchun 7680 dan 8000 ni ayirish.

$$-80x^{2}=-320$$

Ikki tarafini -80 ga bo‘ling.

$$x^{2}=\frac{-320}{-80}$$

4 ni olish uchun -320 ni -80 ga bo‘ling.

$$x^{2}=4$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$x=2 x=-2$$

Kvadrat tenglamalaridan foydalanish qoidalari

Tenglamaning ikkala tarafini 10 ga ko'paytirish.

$$8000\left(1+\frac{x}{10}\right)\left(1-\frac{x}{10}\right)=8000-320$$

8000 ga 1+\frac{x}{10} ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$\left(8000+8000\times \frac{x}{10}\right)\left(1-\frac{x}{10}\right)=8000-320$$

8000 va 10 ichida eng katta umumiy 10 faktorini bekor qiling.

$$\left(8000+800x\right)\left(1-\frac{x}{10}\right)=8000-320$$

8000+800x ifodaning har bir elementini 1-\frac{x}{10} ifodaning har bir elementiga ko‘paytirish orqali taqsimot qonuni xususiyatlarini qo‘llash mumkin.

$$8000+8000\left(-\frac{x}{10}\right)+800x+800x\left(-\frac{x}{10}\right)=8000-320$$

8000 va 10 ichida eng katta umumiy 10 faktorini bekor qiling.

$$8000-800x+800x+800x\left(-\frac{x}{10}\right)=8000-320$$

0 ni olish uchun -800x va 800x ni birlashtirish.

$$8000+800x\left(-\frac{x}{10}\right)=8000-320$$

800 va 10 ichida eng katta umumiy 10 faktorini bekor qiling.

$$8000-80xx=8000-320$$

x^{2} hosil qilish uchun x va x ni ko'paytirish.

$$8000-80x^{2}=8000-320$$

7680 olish uchun 8000 dan 320 ni ayirish.

$$8000-80x^{2}=7680$$

Ikkala tarafdan 7680 ni ayirish.

$$8000-80x^{2}-7680=0$$

320 olish uchun 8000 dan 7680 ni ayirish.

$$320-80x^{2}=0$$

Bu kabi kvadrat tenglamalarni x^{2} sharti bilan, biroq x shartisiz hamon kvadrat tenglamasidan foydalanib yechish mumkin, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, ular standart formulaga solingandan so'ng: ax^{2}+bx+c=0.

$$-80x^{2}+320=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} -80 ni a, 0 ni b va 320 ni c bilan almashtiring.

$$x=\frac{0±\sqrt{0^{2}-4\left(-80\right)\times 320}}{2\left(-80\right)}$$

0 kvadratini chiqarish.

$$x=\frac{0±\sqrt{-4\left(-80\right)\times 320}}{2\left(-80\right)}$$

-4 ni -80 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{320\times 320}}{2\left(-80\right)}$$

320 ni 320 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{102400}}{2\left(-80\right)}$$

102400 ning kvadrat ildizini chiqarish.

$$x=\frac{0±320}{2\left(-80\right)}$$

2 ni -80 marotabaga ko'paytirish.

$$x=\frac{0±320}{-160}$$

x=\frac{0±320}{-160} tenglamasini yeching, bunda ± musbat. 320 ni -160 ga bo'lish.

$$x=-2$$

x=\frac{0±320}{-160} tenglamasini yeching, bunda ± manfiy. -320 ni -160 ga bo'lish.

$$x=2$$

Tenglama yechildi.

$$x=-2 x=2$$