80+40sqrt{2}=5+5+5sqrt{2}*x eching

$$80+40 \sqrt{ 2 } =5+5+5 \sqrt{ 2 } \times x$$

x uchun yechish

$$x=7\sqrt{2}+8\approx 17,899494937$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

10 olish uchun 5 va 5'ni qo'shing.

$$80+40\sqrt{2}=10+5\sqrt{2}x$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$10+5\sqrt{2}x=80+40\sqrt{2}$$

Ikkala tarafdan 10 ni ayirish.

$$5\sqrt{2}x=80+40\sqrt{2}-10$$

70 olish uchun 80 dan 10 ni ayirish.

$$5\sqrt{2}x=70+40\sqrt{2}$$

Tenglama standart shaklda.

$$5\sqrt{2}x=40\sqrt{2}+70$$

Ikki tarafini 5\sqrt{2} ga bo‘ling.

$$\frac{5\sqrt{2}x}{5\sqrt{2}}=\frac{40\sqrt{2}+70}{5\sqrt{2}}$$

5\sqrt{2} ga bo'lish 5\sqrt{2} ga ko'paytirishni bekor qiladi.

$$x=\frac{40\sqrt{2}+70}{5\sqrt{2}}$$

70+40\sqrt{2} ni 5\sqrt{2} ga bo'lish.

$$x=7\sqrt{2}+8$$