80t-16t^2 eching

$$80 t - 16 t ^ { 2 }$$

Omil

$$16t\left(5-t\right)$$

Yechim qadamlari

16 omili.

$$16\left(5t-t^{2}\right)$$

Hisoblang: 5t-t^{2}. t omili.

$$t\left(5-t\right)$$

Toʻliq ajratilgan ifodani qaytadan yozing.

$$16t\left(-t+5\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$-16t^{2}+80t=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$t=\frac{-80±\sqrt{80^{2}}}{2\left(-16\right)}$$

80^{2} ning kvadrat ildizini chiqarish.

$$t=\frac{-80±80}{2\left(-16\right)}$$

2 ni -16 marotabaga ko'paytirish.

$$t=\frac{-80±80}{-32}$$

t=\frac{-80±80}{-32} tenglamasini yeching, bunda ± musbat. -80 ni 80 ga qo'shish.

$$t=\frac{0}{-32}$$

0 ni -32 ga bo'lish.

$$t=0$$

t=\frac{-80±80}{-32} tenglamasini yeching, bunda ± manfiy. -80 dan 80 ni ayirish.

$$t=-\frac{160}{-32}$$

-160 ni -32 ga bo'lish.

$$t=5$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun 0 ga va x_{2} uchun 5 ga bo‘ling.

$$-16t^{2}+80t=-16t\left(t-5\right)$$

Baholash

$$16t\left(5-t\right)$$