80(x+1)^2=1352 eching

$$80 ( x + 1 ) ^ { 2 } = 1352$$

x uchun yechish

$$x=\frac{13\sqrt{10}}{10}-1\approx 3,110960958$$

$$x=-\frac{13\sqrt{10}}{10}-1\approx -5,110960958$$

Kvadrat ildizini topish bo'yicha qadamlar

Ikki tarafini 80 ga bo‘ling.

$$\frac{80\left(x+1\right)^{2}}{80}=\frac{1352}{80}$$

80 ga bo'lish 80 ga ko'paytirishni bekor qiladi.

$$\left(x+1\right)^{2}=\frac{1352}{80}$$

\frac{1352}{80} ulushini 8 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$\left(x+1\right)^{2}=\frac{169}{10}$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$x+1=\frac{13\sqrt{10}}{10} x+1=-\frac{13\sqrt{10}}{10}$$

Tenglamaning ikkala tarafidan 1 ni ayirish.

$$x+1-1=\frac{13\sqrt{10}}{10}-1 x+1-1=-\frac{13\sqrt{10}}{10}-1$$

O‘zidan 1 ayirilsa 0 qoladi.

$$x=\frac{13\sqrt{10}}{10}-1 x=-\frac{13\sqrt{10}}{10}-1$$