8(x-4)+3xleq2(x-1)+10 eching

$$8(x-4)+3x \leq 2(x-1)+10$$

x uchun yechish

$$x\leq \frac{40}{9}$$

Yechim qadamlari

8 ga x-4 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$8x-32+3x\leq 2\left(x-1\right)+10$$

11x ni olish uchun 8x va 3x ni birlashtirish.

$$11x-32\leq 2\left(x-1\right)+10$$

2 ga x-1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$11x-32\leq 2x-2+10$$

8 olish uchun -2 va 10'ni qo'shing.

$$11x-32\leq 2x+8$$

Ikkala tarafdan 2x ni ayirish.

$$11x-32-2x\leq 8$$

9x ni olish uchun 11x va -2x ni birlashtirish.

$$9x-32\leq 8$$

32 ni ikki tarafga qo’shing.

$$9x\leq 8+32$$

40 olish uchun 8 va 32'ni qo'shing.

$$9x\leq 40$$

Ikki tarafini 9 ga bo‘ling. 9 musbat bo‘lgani uchun, tengsizlik yo‘nalishi o‘zgarmaydi.

$$x\leq \frac{40}{9}$$