8x^2+8x+7 eching

$$8 x ^ { 2 } + 8 x + 7$$

x ga nisbatan hosilani topish

$$16x+8$$

Yig'indi uchun derivativ qoidasidan foydalanish qadamlari

Polinomialning hosilasi bu uning shartlari hosilasining yig‘indisiga teng. Konstant shartning hosilasi 0. ax^{n} ning hosilasi nax^{n-1}.

$$2\times 8x^{2-1}+8x^{1-1}$$

2 ni 8 marotabaga ko'paytirish.

$$16x^{2-1}+8x^{1-1}$$

2 dan 1 ni ayirish.

$$16x^{1}+8x^{1-1}$$

1 dan 1 ni ayirish.

$$16x^{1}+8x^{0}$$

Har qanday t sharti uchun t^{1}=t.

$$16x+8x^{0}$$

Har qanday t sharti uchun (0 bundan mustasno) t^{0}=1.

$$16x+8\times 1$$

Har qanday t sharti uchun t\times 1=t va 1t=t.

$$16x+8$$

Baholash

$$8x^{2}+8x+7$$