8(x+1)+1^2<3(2x)-1 eching

$$8 ( x + 1 ) + 1 ^ { 2 } < 3 ( 2 x ) - 1$$

x uchun yechish

$$x<-5$$

Yechim qadamlari

8 ga x+1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$8x+8+1^{2}<3\times 2x-1$$

2 daraja ko‘rsatkichini 1 ga hisoblang va 1 ni qiymatni oling.

$$8x+8+1<3\times 2x-1$$

9 olish uchun 8 va 1'ni qo'shing.

$$8x+9<3\times 2x-1$$

6 hosil qilish uchun 3 va 2 ni ko'paytirish.

$$8x+9<6x-1$$

Ikkala tarafdan 6x ni ayirish.

$$8x+9-6x<-1$$

2x ni olish uchun 8x va -6x ni birlashtirish.

$$2x+9<-1$$

Ikkala tarafdan 9 ni ayirish.

$$2x<-1-9$$

-10 olish uchun -1 dan 9 ni ayirish.

$$2x<-10$$

Ikki tarafini 2 ga bo‘ling. 2 musbat bo‘lgani uchun, tengsizlik yo‘nalishi o‘zgarmaydi.

$$x<\frac{-10}{2}$$

-5 ni olish uchun -10 ni 2 ga bo‘ling.

$$x<-5$$