8^y-2=16 eching

$$8 ^ { y - 2 } = 16$$

y uchun yechish

$$y = \frac{10}{3} = 3\frac{1}{3} \approx 3,333333333$$

Logaritm ifodasidan foydalanish qadamlari

Tenglamani yechish uchun eksponent va logaritmlarning qoidalaridan foydalanish.

$$8^{y-2}=16$$

Tenglamaning ikkala tarafiga tegishli logaritmni chiqarish.

$$\log(8^{y-2})=\log(16)$$

Darajaga ko'tarigan logaritm raqami raqam logaritmining darajasidir.

$$\left(y-2\right)\log(8)=\log(16)$$

Ikki tarafini \log(8) ga bo‘ling.

$$y-2=\frac{\log(16)}{\log(8)}$$

Asosiy tenglamani almashtirish orqali \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).

$$y-2=\log_{8}\left(16\right)$$

2 ni tenglamaning ikkala tarafiga qo'shish.

$$y=\frac{4}{3}-\left(-2\right)$$