8^x*2=128 eching

$$8 ^ { x } \cdot 2 = 128$$

x uchun yechish

$$x=2$$

Logaritm ifodasidan foydalanish qadamlari

Tenglamani yechish uchun eksponent va logaritmlarning qoidalaridan foydalanish.

$$2\times 8^{x}=128$$

Ikki tarafini 2 ga bo‘ling.

$$8^{x}=64$$

Tenglamaning ikkala tarafiga tegishli logaritmni chiqarish.

$$\log(8^{x})=\log(64)$$

Darajaga ko'tarigan logaritm raqami raqam logaritmining darajasidir.

$$x\log(8)=\log(64)$$

Ikki tarafini \log(8) ga bo‘ling.

$$x=\frac{\log(64)}{\log(8)}$$

Asosiy tenglamani almashtirish orqali \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).

$$x=\log_{8}\left(64\right)$$

x uchun yechish (complex solution)

$$x=\frac{2\pi n_{1}i}{3\ln(2)}+2$$

$$n_{1}\in \mathrm{Z}$$