Asosiy tarkibga oʻtish
x uchun yechish (complex solution)
Tick mark Image
Grafik

Veb-qidiruvdagi o'xshash muammolar

Baham ko'rish

72x^{2}-72x+225=0
ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.
x=\frac{-\left(-72\right)±\sqrt{\left(-72\right)^{2}-4\times 72\times 225}}{2\times 72}
Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 72 ni a, -72 ni b va 225 ni c bilan almashtiring.
x=\frac{-\left(-72\right)±\sqrt{5184-4\times 72\times 225}}{2\times 72}
-72 kvadratini chiqarish.
x=\frac{-\left(-72\right)±\sqrt{5184-288\times 225}}{2\times 72}
-4 ni 72 marotabaga ko'paytirish.
x=\frac{-\left(-72\right)±\sqrt{5184-64800}}{2\times 72}
-288 ni 225 marotabaga ko'paytirish.
x=\frac{-\left(-72\right)±\sqrt{-59616}}{2\times 72}
5184 ni -64800 ga qo'shish.
x=\frac{-\left(-72\right)±36\sqrt{46}i}{2\times 72}
-59616 ning kvadrat ildizini chiqarish.
x=\frac{72±36\sqrt{46}i}{2\times 72}
-72 ning teskarisi 72 ga teng.
x=\frac{72±36\sqrt{46}i}{144}
2 ni 72 marotabaga ko'paytirish.
x=\frac{72+36\sqrt{46}i}{144}
x=\frac{72±36\sqrt{46}i}{144} tenglamasini yeching, bunda ± musbat. 72 ni 36i\sqrt{46} ga qo'shish.
x=\frac{\sqrt{46}i}{4}+\frac{1}{2}
72+36i\sqrt{46} ni 144 ga bo'lish.
x=\frac{-36\sqrt{46}i+72}{144}
x=\frac{72±36\sqrt{46}i}{144} tenglamasini yeching, bunda ± manfiy. 72 dan 36i\sqrt{46} ni ayirish.
x=-\frac{\sqrt{46}i}{4}+\frac{1}{2}
72-36i\sqrt{46} ni 144 ga bo'lish.
x=\frac{\sqrt{46}i}{4}+\frac{1}{2} x=-\frac{\sqrt{46}i}{4}+\frac{1}{2}
Tenglama yechildi.
72x^{2}-72x+225=0
Bu kabi kvadrat tenglamalarni kvadratni yakunlab yechish mumkin. Kvadratni yechish uchun tenglama avval ushbu shaklda bo'lishi shart: x^{2}+bx=c.
72x^{2}-72x+225-225=-225
Tenglamaning ikkala tarafidan 225 ni ayirish.
72x^{2}-72x=-225
O‘zidan 225 ayirilsa 0 qoladi.
\frac{72x^{2}-72x}{72}=-\frac{225}{72}
Ikki tarafini 72 ga bo‘ling.
x^{2}+\left(-\frac{72}{72}\right)x=-\frac{225}{72}
72 ga bo'lish 72 ga ko'paytirishni bekor qiladi.
x^{2}-x=-\frac{225}{72}
-72 ni 72 ga bo'lish.
x^{2}-x=-\frac{25}{8}
\frac{-225}{72} ulushini 9 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.
x^{2}-x+\left(-\frac{1}{2}\right)^{2}=-\frac{25}{8}+\left(-\frac{1}{2}\right)^{2}
-1 ni bo‘lish, x shartining koeffitsienti, 2 ga -\frac{1}{2} olish uchun. Keyin, -\frac{1}{2} ning kvadratini tenglamaning ikkala tarafiga qo‘shing. Ushbu qadam tenglamaning chap qismini mukammal kvadrat sifatida hosil qiladi.
x^{2}-x+\frac{1}{4}=-\frac{25}{8}+\frac{1}{4}
Kasrning ham suratini, ham maxrajini kvadratga ko'paytirib -\frac{1}{2} kvadratini chiqarish.
x^{2}-x+\frac{1}{4}=-\frac{23}{8}
Umumiy maxrajni topib va hisoblovchini qo'shish orqali -\frac{25}{8} ni \frac{1}{4} ga qo'shing. So'ngra agar imkoni bo'lsa kasrni eng kam shartga qisqartiring.
\left(x-\frac{1}{2}\right)^{2}=-\frac{23}{8}
x^{2}-x+\frac{1}{4} omili. Odatda, x^{2}+bx+c mukammal kvadrat bo'lsa, u doimo \left(x+\frac{b}{2}\right)^{2} omil sifatida bo'lishi mumkin.
\sqrt{\left(x-\frac{1}{2}\right)^{2}}=\sqrt{-\frac{23}{8}}
Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.
x-\frac{1}{2}=\frac{\sqrt{46}i}{4} x-\frac{1}{2}=-\frac{\sqrt{46}i}{4}
Qisqartirish.
x=\frac{\sqrt{46}i}{4}+\frac{1}{2} x=-\frac{\sqrt{46}i}{4}+\frac{1}{2}
\frac{1}{2} ni tenglamaning ikkala tarafiga qo'shish.