7(3-x)geq5 eching

$$7 ( 3 - x ) \geq 5$$

x uchun yechish

$$x\leq \frac{16}{7}$$

Yechim qadamlari

Ikki tarafini 7 ga bo‘ling. 7 >0 bo‘lganda, tengsizlikning yo‘nalishi o‘zgarmasdan qoladi.

$$3-x\geq \frac{5}{7}$$

Ikkala tarafdan 3 ni ayirish.

$$-x\geq \frac{5}{7}-3$$

3 ni \frac{21}{7} kasrga o‘giring.

$$-x\geq \frac{5}{7}-\frac{21}{7}$$

\frac{5}{7} va \frac{21}{7} da bir xil maxraji bor, ularning suratini ayirish orqali ayiring.

$$-x\geq \frac{5-21}{7}$$

-16 olish uchun 5 dan 21 ni ayirish.

$$-x\geq -\frac{16}{7}$$

Ikki tarafini -1 ga bo‘ling. -1 <0 bo‘lganda, tengsizlikning yo‘nalishi o‘zgargan bo‘ladi.

$$x\leq \frac{-\frac{16}{7}}{-1}$$

\frac{-\frac{16}{7}}{-1} ni yagona kasrga aylantiring.

$$x\leq \frac{-16}{7\left(-1\right)}$$

-7 hosil qilish uchun 7 va -1 ni ko'paytirish.

$$x\leq \frac{-16}{-7}$$

Ikkala surat va maxrajdan manfiy belgini olib tashlash bilan \frac{-16}{-7} kasrini \frac{16}{7} ga soddalashtirish mumkin.

$$x\leq \frac{16}{7}$$