7(3-x)geq15 eching

$$7 ( 3 - x ) \geq 15$$

x uchun yechish

$$x\leq \frac{6}{7}$$

Yechim qadamlari

Ikki tarafini 7 ga bo‘ling. 7 musbat bo‘lgani uchun, tengsizlik yo‘nalishi o‘zgarmaydi.

$$3-x\geq \frac{15}{7}$$

Ikkala tarafdan 3 ni ayirish.

$$-x\geq \frac{15}{7}-3$$

3 ni \frac{21}{7} kasrga o‘giring.

$$-x\geq \frac{15}{7}-\frac{21}{7}$$

\frac{15}{7} va \frac{21}{7} da bir xil maxraji bor, ularning suratini ayirish orqali ayiring.

$$-x\geq \frac{15-21}{7}$$

-6 olish uchun 15 dan 21 ni ayirish.

$$-x\geq -\frac{6}{7}$$

Ikki tarafini -1 ga bo‘ling. -1 manfiy boʻlgani uchun tengsizlikning yo‘nalishi o‘zgaradi.

$$x\leq \frac{-\frac{6}{7}}{-1}$$

\frac{-\frac{6}{7}}{-1} ni yagona kasrga aylantiring.

$$x\leq \frac{-6}{7\left(-1\right)}$$

-7 hosil qilish uchun 7 va -1 ni ko'paytirish.

$$x\leq \frac{-6}{-7}$$

Ikkala surat va maxrajdan manfiy belgini olib tashlash bilan \frac{-6}{-7} kasrini \frac{6}{7} ga soddalashtirish mumkin.

$$x\leq \frac{6}{7}$$