65^3sqrt{x^6}dx=5 eching

$$65 ^ { 3 } \sqrt { x ^ { 6 } } d x = 5$$

d uchun yechish

$$d=\frac{1}{54925x\left(|x|\right)^{3}}$$

$$x\neq 0$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

3 daraja ko‘rsatkichini 65 ga hisoblang va 274625 ni qiymatni oling.

$$274625\sqrt{x^{6}}dx=5$$

Tenglama standart shaklda.

$$274625x\sqrt{x^{6}}d=5$$

Ikki tarafini 274625\sqrt{x^{6}}x ga bo‘ling.

$$\frac{274625x\sqrt{x^{6}}d}{274625x\sqrt{x^{6}}}=\frac{5}{274625x\sqrt{x^{6}}}$$

274625\sqrt{x^{6}}x ga bo'lish 274625\sqrt{x^{6}}x ga ko'paytirishni bekor qiladi.

$$d=\frac{5}{274625x\sqrt{x^{6}}}$$

5 ni 274625\sqrt{x^{6}}x ga bo'lish.

$$d=\frac{1}{54925x\left(|x|\right)^{3}}$$

x uchun yechish

$$\left\{\begin{matrix}x=\frac{\sqrt{5}\sqrt[4]{\frac{13}{d}}}{65}\text{, }&d>0\\x=-\frac{\sqrt{5}\sqrt[4]{-\frac{13}{d}}}{65}\text{, }&d<0\end{matrix}\right,$$