6280=1/3*314*(20)^2*h eching

$$6280 = \frac { 1 } { 3 } \times 314 \times ( 20 ) ^ { 2 } \times h$$

h uchun yechish

$$h=\frac{3}{20}=0,15$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

\frac{314}{3} hosil qilish uchun \frac{1}{3} va 314 ni ko'paytirish.

$$6280=\frac{314}{3}\times 20^{2}h$$

2 daraja ko‘rsatkichini 20 ga hisoblang va 400 ni qiymatni oling.

$$6280=\frac{314}{3}\times 400h$$

\frac{314}{3}\times 400 ni yagona kasrga aylantiring.

$$6280=\frac{314\times 400}{3}h$$

125600 hosil qilish uchun 314 va 400 ni ko'paytirish.

$$6280=\frac{125600}{3}h$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$\frac{125600}{3}h=6280$$

Ikki tarafini \frac{3}{125600} va teskari kasri \frac{125600}{3} ga ko‘paytiring.

$$h=6280\times \frac{3}{125600}$$

6280\times \frac{3}{125600} ni yagona kasrga aylantiring.

$$h=\frac{6280\times 3}{125600}$$

18840 hosil qilish uchun 6280 va 3 ni ko'paytirish.

$$h=\frac{18840}{125600}$$

\frac{18840}{125600} ulushini 6280 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$h=\frac{3}{20}$$