6(x+2)>7(x-5) eching

$$6(x+2) > 7(x-5)$$

x uchun yechish

$$x<47$$

Yechim qadamlari

6 ga x+2 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$6x+12>7\left(x-5\right)$$

7 ga x-5 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$6x+12>7x-35$$

Ikkala tarafdan 7x ni ayirish.

$$6x+12-7x>-35$$

-x ni olish uchun 6x va -7x ni birlashtirish.

$$-x+12>-35$$

Ikkala tarafdan 12 ni ayirish.

$$-x>-35-12$$

-47 olish uchun -35 dan 12 ni ayirish.

$$-x>-47$$

Ikki tarafini -1 ga bo‘ling. -1 manfiy boʻlgani uchun tengsizlikning yo‘nalishi o‘zgaradi.

$$x<\frac{-47}{-1}$$

Ikkala surat va maxrajdan manfiy belgini olib tashlash bilan \frac{-47}{-1} kasrini 47 ga soddalashtirish mumkin.

$$x<47$$