6y-2y^2 eching

$$6 y - 2 y ^ { 2 }$$

Omil

$$2y\left(3-y\right)$$

Yechim qadamlari

2 omili.

$$2\left(3y-y^{2}\right)$$

Hisoblang: 3y-y^{2}. y omili.

$$y\left(3-y\right)$$

Toʻliq ajratilgan ifodani qaytadan yozing.

$$2y\left(-y+3\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$-2y^{2}+6y=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$y=\frac{-6±\sqrt{6^{2}}}{2\left(-2\right)}$$

6^{2} ning kvadrat ildizini chiqarish.

$$y=\frac{-6±6}{2\left(-2\right)}$$

2 ni -2 marotabaga ko'paytirish.

$$y=\frac{-6±6}{-4}$$

y=\frac{-6±6}{-4} tenglamasini yeching, bunda ± musbat. -6 ni 6 ga qo'shish.

$$y=\frac{0}{-4}$$

0 ni -4 ga bo'lish.

$$y=0$$

y=\frac{-6±6}{-4} tenglamasini yeching, bunda ± manfiy. -6 dan 6 ni ayirish.

$$y=-\frac{12}{-4}$$

-12 ni -4 ga bo'lish.

$$y=3$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun 0 ga va x_{2} uchun 3 ga bo‘ling.

$$-2y^{2}+6y=-2y\left(y-3\right)$$

Baholash

$$2y\left(3-y\right)$$