6x(3x-1)^2+2x^2(1-3x)^2 eching

$$6 x ( 3 x - 1 ) ^ { 2 } + 2 x ^ { 2 } ( 1 - 3 x ) ^ { 2 }$$

Baholash

$$2x\left(x+3\right)\left(3x-1\right)^{2}$$

Yechim qadamlari

\left(a-b\right)^{2}=a^{2}-2ab+b^{2} binom teoremasini \left(3x-1\right)^{2} kengaytirilishi uchun ishlating.

$$6x\left(9x^{2}-6x+1\right)+2x^{2}\left(1-3x\right)^{2}$$

6x ga 9x^{2}-6x+1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$54x^{3}-36x^{2}+6x+2x^{2}\left(1-3x\right)^{2}$$

\left(a-b\right)^{2}=a^{2}-2ab+b^{2} binom teoremasini \left(1-3x\right)^{2} kengaytirilishi uchun ishlating.

$$54x^{3}-36x^{2}+6x+2x^{2}\left(1-6x+9x^{2}\right)$$

2x^{2} ga 1-6x+9x^{2} ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$54x^{3}-36x^{2}+6x+2x^{2}-12x^{3}+18x^{4}$$

-34x^{2} ni olish uchun -36x^{2} va 2x^{2} ni birlashtirish.

$$54x^{3}-34x^{2}+6x-12x^{3}+18x^{4}$$

42x^{3} ni olish uchun 54x^{3} va -12x^{3} ni birlashtirish.

$$42x^{3}-34x^{2}+6x+18x^{4}$$

Kengaytirish

$$18x^{4}+42x^{3}-34x^{2}+6x$$

Yechim qadamlari

\left(a-b\right)^{2}=a^{2}-2ab+b^{2} binom teoremasini \left(3x-1\right)^{2} kengaytirilishi uchun ishlating.

$$6x\left(9x^{2}-6x+1\right)+2x^{2}\left(1-3x\right)^{2}$$

6x ga 9x^{2}-6x+1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$54x^{3}-36x^{2}+6x+2x^{2}\left(1-3x\right)^{2}$$

\left(a-b\right)^{2}=a^{2}-2ab+b^{2} binom teoremasini \left(1-3x\right)^{2} kengaytirilishi uchun ishlating.

$$54x^{3}-36x^{2}+6x+2x^{2}\left(1-6x+9x^{2}\right)$$

2x^{2} ga 1-6x+9x^{2} ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$54x^{3}-36x^{2}+6x+2x^{2}-12x^{3}+18x^{4}$$

-34x^{2} ni olish uchun -36x^{2} va 2x^{2} ni birlashtirish.

$$54x^{3}-34x^{2}+6x-12x^{3}+18x^{4}$$

42x^{3} ni olish uchun 54x^{3} va -12x^{3} ni birlashtirish.

$$42x^{3}-34x^{2}+6x+18x^{4}$$