6x^2-5x-5 eching

$$6 x ^ { 2 } - 5 x - 5$$

Omil

$$6\left(x-\frac{5-\sqrt{145}}{12}\right)\left(x-\frac{\sqrt{145}+5}{12}\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$6x^{2}-5x-5=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$x=\frac{-\left(-5\right)±\sqrt{\left(-5\right)^{2}-4\times 6\left(-5\right)}}{2\times 6}$$

-5 kvadratini chiqarish.

$$x=\frac{-\left(-5\right)±\sqrt{25-4\times 6\left(-5\right)}}{2\times 6}$$

-4 ni 6 marotabaga ko'paytirish.

$$x=\frac{-\left(-5\right)±\sqrt{25-24\left(-5\right)}}{2\times 6}$$

-24 ni -5 marotabaga ko'paytirish.

$$x=\frac{-\left(-5\right)±\sqrt{25+120}}{2\times 6}$$

25 ni 120 ga qo'shish.

$$x=\frac{-\left(-5\right)±\sqrt{145}}{2\times 6}$$

-5 ning teskarisi 5 ga teng.

$$x=\frac{5±\sqrt{145}}{2\times 6}$$

2 ni 6 marotabaga ko'paytirish.

$$x=\frac{5±\sqrt{145}}{12}$$

x=\frac{5±\sqrt{145}}{12} tenglamasini yeching, bunda ± musbat. 5 ni \sqrt{145} ga qo'shish.

$$x=\frac{\sqrt{145}+5}{12}$$

x=\frac{5±\sqrt{145}}{12} tenglamasini yeching, bunda ± manfiy. 5 dan \sqrt{145} ni ayirish.

$$x=\frac{5-\sqrt{145}}{12}$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun \frac{5+\sqrt{145}}{12} ga va x_{2} uchun \frac{5-\sqrt{145}}{12} ga bo‘ling.

$$6x^{2}-5x-5=6\left(x-\frac{\sqrt{145}+5}{12}\right)\left(x-\frac{5-\sqrt{145}}{12}\right)$$

Baholash

$$6x^{2}-5x-5$$