6x^2+42x eching

$$6 x ^ { 2 } + 42 x$$

Omil

$$6x\left(x+7\right)$$

Yechim qadamlari

6 omili.

$$6\left(x^{2}+7x\right)$$

Hisoblang: x^{2}+7x. x omili.

$$x\left(x+7\right)$$

Toʻliq ajratilgan ifodani qaytadan yozing.

$$6x\left(x+7\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$6x^{2}+42x=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$x=\frac{-42±\sqrt{42^{2}}}{2\times 6}$$

42^{2} ning kvadrat ildizini chiqarish.

$$x=\frac{-42±42}{2\times 6}$$

2 ni 6 marotabaga ko'paytirish.

$$x=\frac{-42±42}{12}$$

x=\frac{-42±42}{12} tenglamasini yeching, bunda ± musbat. -42 ni 42 ga qo'shish.

$$x=\frac{0}{12}$$

0 ni 12 ga bo'lish.

$$x=0$$

x=\frac{-42±42}{12} tenglamasini yeching, bunda ± manfiy. -42 dan 42 ni ayirish.

$$x=-\frac{84}{12}$$

-84 ni 12 ga bo'lish.

$$x=-7$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun 0 ga va x_{2} uchun -7 ga bo‘ling.

$$6x^{2}+42x=6x\left(x-\left(-7\right)\right)$$

p-\left(-q\right) shaklining barcha amallarigani p+q ga soddalashtiring.

$$6x^{2}+42x=6x\left(x+7\right)$$

Baholash

$$6x\left(x+7\right)$$