6-2(x+1)leq3(1-2x) eching

$$6 - 2 ( x + 1 ) \leq 3 ( 1 - 2 x )$$

x uchun yechish

$$x\leq -\frac{1}{4}$$

Yechim qadamlari

-2 ga x+1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$6-2x-2\leq 3\left(1-2x\right)$$

4 olish uchun 6 dan 2 ni ayirish.

$$4-2x\leq 3\left(1-2x\right)$$

3 ga 1-2x ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$4-2x\leq 3-6x$$

6x ni ikki tarafga qo’shing.

$$4-2x+6x\leq 3$$

4x ni olish uchun -2x va 6x ni birlashtirish.

$$4+4x\leq 3$$

Ikkala tarafdan 4 ni ayirish.

$$4x\leq 3-4$$

-1 olish uchun 3 dan 4 ni ayirish.

$$4x\leq -1$$

Ikki tarafini 4 ga bo‘ling. 4 musbat bo‘lgani uchun, tengsizlik yo‘nalishi o‘zgarmaydi.

$$x\leq -\frac{1}{4}$$