6^2+(16-x)^2=x^2 eching

$$6 ^ { 2 } + ( 16 - x ) ^ { 2 } = x ^ { 2 }$$

x uchun yechish

$$x = \frac{73}{8} = 9\frac{1}{8} = 9,125$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

2 daraja ko‘rsatkichini 6 ga hisoblang va 36 ni qiymatni oling.

$$36+\left(16-x\right)^{2}=x^{2}$$

\left(a-b\right)^{2}=a^{2}-2ab+b^{2} binom teoremasini \left(16-x\right)^{2} kengaytirilishi uchun ishlating.

$$36+256-32x+x^{2}=x^{2}$$

292 olish uchun 36 va 256'ni qo'shing.

$$292-32x+x^{2}=x^{2}$$

Ikkala tarafdan x^{2} ni ayirish.

$$292-32x+x^{2}-x^{2}=0$$

0 ni olish uchun x^{2} va -x^{2} ni birlashtirish.

$$292-32x=0$$

Ikkala tarafdan 292 ni ayirish. Har qanday sonni noldan ayirsangiz, o‘zining manfiyi chiqadi.

$$-32x=-292$$

Ikki tarafini -32 ga bo‘ling.

$$x=\frac{-292}{-32}$$

\frac{-292}{-32} ulushini -4 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$x=\frac{73}{8}$$