6+x<12+x+20+x eching

$$6 + x < 12 + x + 20 + x$$

x uchun yechish

$$x>-26$$

Yechim qadamlari

32 olish uchun 12 va 20'ni qo'shing.

$$6+x<32+x+x$$

2x ni olish uchun x va x ni birlashtirish.

$$6+x<32+2x$$

Ikkala tarafdan 2x ni ayirish.

$$6+x-2x<32$$

-x ni olish uchun x va -2x ni birlashtirish.

$$6-x<32$$

Ikkala tarafdan 6 ni ayirish.

$$-x<32-6$$

26 olish uchun 32 dan 6 ni ayirish.

$$-x<26$$

Ikki tarafini -1 ga bo‘ling. -1 manfiy boʻlgani uchun tengsizlikning yo‘nalishi o‘zgaradi.

$$x>-26$$