5z5y=5x15z^2 eching

$$5z5y=5x15 { z }^{ 2 }$$

x_15 uchun yechish

$$\left\{\begin{matrix}x_{15}=\frac{yz_{5}}{z^{2}}\text{, }&z\neq 0\\x_{15}\in \mathrm{R}\text{, }&\left(z_{5}=0\text{ or }y=0\right)\text{ and }z=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

5ni ikki tarafidan bekor qilish.

$$z_{5}y=x_{15}z^{2}$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$x_{15}z^{2}=z_{5}y$$

Tenglama standart shaklda.

$$z^{2}x_{15}=yz_{5}$$

Ikki tarafini z^{2} ga bo‘ling.

$$\frac{z^{2}x_{15}}{z^{2}}=\frac{yz_{5}}{z^{2}}$$

z^{2} ga bo'lish z^{2} ga ko'paytirishni bekor qiladi.

$$x_{15}=\frac{yz_{5}}{z^{2}}$$

y uchun yechish

$$\left\{\begin{matrix}y=\frac{x_{15}z^{2}}{z_{5}}\text{, }&z_{5}\neq 0\\y\in \mathrm{R}\text{, }&\left(x_{15}=0\text{ or }z=0\right)\text{ and }z_{5}=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

5ni ikki tarafidan bekor qilish.

$$z_{5}y=x_{15}z^{2}$$

Ikki tarafini z_{5} ga bo‘ling.

$$\frac{z_{5}y}{z_{5}}=\frac{x_{15}z^{2}}{z_{5}}$$

z_{5} ga bo'lish z_{5} ga ko'paytirishni bekor qiladi.

$$y=\frac{x_{15}z^{2}}{z_{5}}$$