51x^4+3x^2+x+2 eching

$$51 x ^ { 4 } + 3 x ^ { 2 } + x + 2$$

x ga nisbatan hosilani topish

$$204x^{3}+6x+1$$

Yig'indi uchun derivativ qoidasidan foydalanish qadamlari

Polinomialning hosilasi bu uning shartlari hosilasining yig‘indisiga teng. Konstant shartning hosilasi 0. ax^{n} ning hosilasi nax^{n-1}.

$$4\times 51x^{4-1}+2\times 3x^{2-1}+x^{1-1}$$

4 ni 51 marotabaga ko'paytirish.

$$204x^{4-1}+2\times 3x^{2-1}+x^{1-1}$$

4 dan 1 ni ayirish.

$$204x^{3}+2\times 3x^{2-1}+x^{1-1}$$

2 ni 3 marotabaga ko'paytirish.

$$204x^{3}+6x^{2-1}+x^{1-1}$$

2 dan 1 ni ayirish.

$$204x^{3}+6x^{1}+x^{1-1}$$

1 dan 1 ni ayirish.

$$204x^{3}+6x^{1}+x^{0}$$

Har qanday t sharti uchun t^{1}=t.

$$204x^{3}+6x+x^{0}$$

Har qanday t sharti uchun (0 bundan mustasno) t^{0}=1.

$$204x^{3}+6x+1$$

Baholash

$$51x^{4}+3x^{2}+x+2$$