50left(1-xright)^2=405 eching

$$50 { \left(1-x \right) }^{ 2 } = 405$$

x uchun yechish

$$x=-\frac{9\sqrt{10}}{10}+1\approx -1,846049894$$

$$x=\frac{9\sqrt{10}}{10}+1\approx 3,846049894$$

Kvadrat ildizini topish bo'yicha qadamlar

Ikki tarafini 50 ga bo‘ling.

$$\frac{50\left(-x+1\right)^{2}}{50}=\frac{405}{50}$$

50 ga bo'lish 50 ga ko'paytirishni bekor qiladi.

$$\left(-x+1\right)^{2}=\frac{405}{50}$$

\frac{405}{50} ulushini 5 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$\left(-x+1\right)^{2}=\frac{81}{10}$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$-x+1=\frac{9\sqrt{10}}{10} -x+1=-\frac{9\sqrt{10}}{10}$$

Tenglamaning ikkala tarafidan 1 ni ayirish.

$$-x+1-1=\frac{9\sqrt{10}}{10}-1 -x+1-1=-\frac{9\sqrt{10}}{10}-1$$

O‘zidan 1 ayirilsa 0 qoladi.

$$-x=\frac{9\sqrt{10}}{10}-1 -x=-\frac{9\sqrt{10}}{10}-1$$

\frac{9\sqrt{10}}{10} dan 1 ni ayirish.

$$-x=\frac{9\sqrt{10}}{10}-1$$

-\frac{9\sqrt{10}}{10} dan 1 ni ayirish.

$$-x=-\frac{9\sqrt{10}}{10}-1$$

Ikki tarafini -1 ga bo‘ling.

$$\frac{-x}{-1}=\frac{\frac{9\sqrt{10}}{10}-1}{-1} \frac{-x}{-1}=\frac{-\frac{9\sqrt{10}}{10}-1}{-1}$$

-1 ga bo'lish -1 ga ko'paytirishni bekor qiladi.

$$x=\frac{\frac{9\sqrt{10}}{10}-1}{-1} x=\frac{-\frac{9\sqrt{10}}{10}-1}{-1}$$

\frac{9\sqrt{10}}{10}-1 ni -1 ga bo'lish.

$$x=-\frac{9\sqrt{10}}{10}+1$$

-\frac{9\sqrt{10}}{10}-1 ni -1 ga bo'lish.

$$x=\frac{9\sqrt{10}}{10}+1$$

Tenglama yechildi.

$$x=-\frac{9\sqrt{10}}{10}+1 x=\frac{9\sqrt{10}}{10}+1$$